Brackets Out, Brackets In
The problem starts with choosing three distinct, non-zero integers between -5 and 5 that do not sum to zero. These are then used in a six factorisations that make use of different permutations of the chosen numbers. Each factorisation is then expanded and the result summed. The result is that (x + 1) is always a factor of the resulting expression.
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|Published||2010 to date|
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